Calorimetry Worksheet 2 Answers Chemsheets Official

Since specific questions from Calorimetry Worksheet 2 by ChemSheets are not provided, a general approach to finding answers includes:

Data:
Mass of water = 200 g
Initial temp = 19.2 °C
Final temp = 37.8 °C
Mass of ethanol burned = 0.46 g
( M_r(\textC_2\textH_5\textOH) = 46.0 )

Step 1 – Heat absorbed by water
[ q = 200 \times 4.18 \times (37.8 - 19.2) ] [ q = 200 \times 4.18 \times 18.6 ] [ q = 15549.6 \ \textJ \approx 15.55 \ \textkJ ]

Step 2 – Moles of ethanol burned
[ n = \frac0.4646.0 = 0.0100 \ \textmol ] calorimetry worksheet 2 answers chemsheets

Step 3 – Molar enthalpy of combustion
[ \Delta H = -\frac15.550.0100 = -1555 \ \textkJ mol^-1 ] (Negative because heat given out.)

Answer: (-1555 \ \textkJ mol^-1)


Question: 0.25 g of ethanol (C₂H₅OH) is burned, heating 150 g of water from 20.0°C to 45.5°C. Calculate ΔH_combustion in kJ/mol. Since specific questions from Calorimetry Worksheet 2 by

Step 1 – Heat gained by water
q = m × c × ΔT = 150 × 4.18 × (45.5 – 20.0)
q = 150 × 4.18 × 25.5
q = 15,988.5 J = 16.0 kJ

Step 2 – Moles of ethanol burned
Molar mass C₂H₅OH = (2×12) + (6×1) + 16 = 46 g/mol
Moles = 0.25 / 46 = 0.005434 mol

Step 3 – Heat per mole
q_per_mol = 16.0 kJ / 0.005434 mol = 2944 kJ/mol Question: 0

Step 4 – Sign
Temp increased → exothermic → negative
Final answer: –2940 kJ/mol (3 sig figs)

There are several types of calorimeters and calorimetric techniques, including:

If you need the exact Chemsheets answers with teacher notes:

Calorimetry is a method used to measure the heat change (ΔH) in a chemical reaction. It involves using a calorimeter to measure the temperature change of a solution or substance during a reaction.

Unlock accurate, step-by-step solutions for Chemsheets Calorimetry Worksheet 2.
Designed for A-level and high school chemistry students, this answer key does more than just provide final numbers—it guides you through the thermodynamic calculations needed to master heat transfer, specific heat capacity, and enthalpy change.