Resource Type: Educational Textbook / Solved Test Collection Target Audience: High School Students (Grade 11), Mathematics Teachers Publisher: Pegi
Zgjidh ekuacionin: tg x = √3 për x ∈ [0, 2π) Matematika 11 Pegi Teste Te Zgjidhura --39-LINK--39-
Zgjidhje:
tg x = √3 → x = π/3 + kπ, k∈Z
Në [0, 2π) kemi:
për k = 0 → x = π/3
për k = 1 → x = π/3 + π = 4π/3
Zgjidhjet: π/3, 4π/3 Resource Type: Educational Textbook / Solved Test Collection
| Problem # | My mistake | Correct method (from solved test) | Rule/Formula to review | |-----------|------------|------------------------------------|--------------------------| k∈Z Në [0
Shembull i zgjidhur:
Zgjidh ekuacionin log₂(x+3) + log₂(x-1) = 3
Hapat: